“Some flowers grow best in the Sun while others do well in Shade.
Remember, we are put where we grow the best and accordingly we get people and situations to grow with”
So, just how much data is in that file? The exact contents of a file may not be precisely known. Usually the general format style of the file and the type of data contained within the file are known. The amount of data stored in the file, however, is often unknown. So, do we spend our time counting data in a text file by hand, or do we let the computer deal with the amount of data? Of course, we let the computer do the counting. |  |
| Rules for using end-of-file (eof( )): 1. Always test for the end-of-file condition before processing data read from an input file stream. a. use a priming input statement before starting the loop b. repeat the input statement at the bottom of the loop body 2. Use a while loop for getting data from an input file stream. A for loop is desirable only when you know the exact number of data items in the file, which we do not know. |
#include
#include
/* required for the malloc, calloc and free functions */
int main() {
float *calloc1, *calloc2, *malloc1, *malloc2;
int i;
calloc1 = calloc(3, sizeof(float)); /* might need to cast */
calloc2 = calloc(3, sizeof(float));
malloc1 = malloc(3 * sizeof(float));
malloc2 = malloc(3 * sizeof(float));
if(calloc1!=NULL && calloc2!=NULL && malloc1!=NULL && malloc2!=NULL) {
for(i=0 ; i<3 ; i++) {
printf("calloc1[%d] holds %05.5f, ", i, calloc1[i]);
printf("malloc1[%d] holds %05.5f\n", i, malloc1[i]);
printf("calloc2[%d] holds %05.5f, ", i, *(calloc2+i));
printf("malloc2[%d] holds %05.5f\n", i, *(malloc2+i));
}
free(calloc1);
free(calloc2);
free(malloc1);
free(malloc2);
return 0;
}
else {
printf("Not enough memory\n");
return 1;
}
} Output: calloc1[0] holds 0.00000, malloc1[0] holds -431602080.00000 |
#include
#include /* required for the malloc and free functions */
int main() {
int number;
int *ptr;
int i;
printf("How many ints would you like store? ");
scanf("%d", &number);
ptr = malloc(number*sizeof(int)); /* allocate memory */
if(ptr!=NULL) {
for(i=0 ; i
*(ptr+i) = i;
}
for(i=number ; i>0 ; i--) {
printf("%d\n", *(ptr+(i-1))); /* print out in reverse order */
}
free(ptr); /* free allocated memory */
return 0;
}
else {
printf("\nMemory allocation failed - not enough memory.\n");
return 1;
}
} Output if I entered 3: How many ints would you like store? 3 |
"Everything that is not explicitly authorised is prohibited"
Modified By Blogcrowds